Solution Manual Microelectronic Circuits 8th Edition by Adel Sedra ,Kenneth Smith (Complete)

Microelectronic Circuits 8th Edition Adel Sedra Solution Manual COmplete EIGHTH INTERNATIONAL EDITION Instructor’s solution manual for Microelectronic Circuits Adel S. Sedra Exercise 1–1 Rs Chapter 1  Solutions to Exercises within the Chapter vs (t)   Ex: 1.1 When output terminals are open-circuited, as in Fig. 1.1a: RL  For circuit a. v oc = v s (t) Given v s (t) = 10 mV and Rs = 1 k. For circuit b. v oc = is (t) × Rs When output terminals are short-circuited, as in Fig. 1.1b: For circuit a. isc = vo v s (t) Rs If RL = 100 k v o = 10 mV × 100 = 9.9 mV 100 + 1 If RL = 10 k For circuit b. isc = is (t) v o = 10 mV × For equivalency If RL = 1 k Rs is (t) = v s (t) v o = 10 mV × Rs a 10  9.1 mV 10 + 1 1 = 5 mV 1+1 If RL = 100  v o = 10 mV × vs (t)   100  0.91 mV 100 + 1 K For v o = 0.8v s , RL = 0.8 RL + Rs b Since Rs = 1 k, Figure 1.1a RL = 4 k a Ex: 1.4 Using current divider: is (t) io Rs is  10 A Rs RL b Figure 1.1b io = i s × Ex: 1.2 Rs Rs + RL Given is = 10 µA, Rs = 100 k. For Rs voc  vs isc   RL = 1 k, io = 10 µA × 100 = 9.9 µA 100 + 1 For RL = 10 k, io = 10 µA × For v oc = 10 mV RL = 100 k, io = 10 µA × isc = 10 µA Rs = Sedra, Smith, Carusone, Gaudet 100 K 100 K + 1 M  0.9 µA Ex: 1.3 Using voltage divider: RL Rs + RL 100 = 5 µA 100 + 100 For RL = 1 M, io = 10 µA × v oc 10 mV = 1 k = isc 10 µA v o (t) = v s (t) × 100  9.1 µA 100 + 10 For io = 0.8is , 100 = 0.8 100 + RL ⇒ RL = 25 k Microelectronic Circuits, 8th International Edition